What are the solutions to the equation 5(3x-3)^2-44=-29 ?

The solutions to the equation 5(3x-3)^2-44=-29 are x=(1+sqrt(3))/(sqrt(3)),x=(-1+sqrt(3))/(sqrt(3))

Find the zeros of 5(3x-3)^2-44=-29

The zeros of 5(3x-3)^2-44=-29 are x=(1+sqrt(3))/(sqrt(3)),x=(-1+sqrt(3))/(sqrt(3))

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5 (3 x - 3)^{2} - 44 = - 29

x = \frac{1 + 3}{3}, x = \frac{- 1 + 3}{3}

Decimal

x = 1.57735 \dots, x = 0.42264 \dots

Solution steps

5 (3 x - 3)^{2} - 44 = - 29

Move

44

to the right side

5 (3 x - 3)^{2} = 15

Divide both sides by

5

(3 x - 3)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 3 = 3 : x = \frac{1 + 3}{3}

Solve

3 x - 3 = - 3 : x = \frac{- 1 + 3}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 3}{3}, x = \frac{- 1 + 3}{3}

3 = 6 x^{2} + 6 x - 9

4 x^{2} - 3 x = - 3

3 x^{2} - 4 x - 4 = 3

9 r^{2} + 6 r + 4 = 0

16 (4 x - 5)^{2} = 9

What are the solutions to the equation 5(3x-3)^2-44=-29 ?
The solutions to the equation 5(3x-3)^2-44=-29 are x=(1+sqrt(3))/(sqrt(3)),x=(-1+sqrt(3))/(sqrt(3))
Find the zeros of 5(3x-3)^2-44=-29
The zeros of 5(3x-3)^2-44=-29 are x=(1+sqrt(3))/(sqrt(3)),x=(-1+sqrt(3))/(sqrt(3))