What are the solutions to the equation roots (x-150)^2+16 ?

The solutions to the equation roots (x-150)^2+16 are x=4i+150,x=-4i+150

Find the zeros of roots (x-150)^2+16

The zeros of roots (x-150)^2+16 are x=4i+150,x=-4i+150

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roots

(x - 150)^{2} + 16

x = 4 i + 150, x = - 4 i + 150

Solution steps

(x - 150)^{2} + 16

The roots are the intercepts with the x-axis

(y = 0)

(x - 150)^{2} + 16 = 0

Move

16

to the right side

(x - 150)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 150 = - 16 : x = 4 i + 150

Solve

x - 150 = - - 16 : x = - 4 i + 150

The solutions to the quadratic equation are:

x = 4 i + 150, x = - 4 i + 150

2 x^{2} - x = 120

x^{2} - 9 x - 20 = - 2 x - 2

(y + 14)^{2} + y^{2} - 25 = 0

y, x^{2} + y^{2} = - 5

y, x^{2} + y^{2} = - 4

What are the solutions to the equation roots (x-150)^2+16 ?
The solutions to the equation roots (x-150)^2+16 are x=4i+150,x=-4i+150
Find the zeros of roots (x-150)^2+16
The zeros of roots (x-150)^2+16 are x=4i+150,x=-4i+150