What are the solutions to the equation roots 2x^2-5x+2 ?

The solutions to the equation roots 2x^2-5x+2 are x=2,x= 1/2

Find the zeros of roots 2x^2-5x+2

The zeros of roots 2x^2-5x+2 are x=2,x= 1/2

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roots

2 x^{2} - 5 x + 2

x = 2, x = \frac{1}{2}

Solution steps

2 x^{2} - 5 x + 2

The roots are the intercepts with the x-axis

(y = 0)

2 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 2 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 2}

x = \frac{- ( - 5 ) + 3}{2 \cdot 2} : 2

x = \frac{- ( - 5 ) - 3}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{2}

3 x^{2} + 6 x - 60

- 2 x^{2} - 36 x - 154 = 0

2 n^{2} - 3 = - 12

3 x^{2} + 32 x + 76 = 7

x^{2} + x = - 12

What are the solutions to the equation roots 2x^2-5x+2 ?
The solutions to the equation roots 2x^2-5x+2 are x=2,x= 1/2
Find the zeros of roots 2x^2-5x+2
The zeros of roots 2x^2-5x+2 are x=2,x= 1/2