What are the solutions to the equation solvefor x,0=12x^2-96x+135 ?

The solutions to the equation solvefor x,0=12x^2-96x+135 are x=(8+sqrt(19))/2 ,x=(8-sqrt(19))/2

Find the zeros of solvefor x,0=12x^2-96x+135

The zeros of solvefor x,0=12x^2-96x+135 are x=(8+sqrt(19))/2 ,x=(8-sqrt(19))/2

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x, 0 = 12 x^{2} - 96 x + 135

x = \frac{8 + 19}{2}, x = \frac{8 - 19}{2}

Decimal

x = 6.17944 \dots, x = 1.82055 \dots

Solution steps

0 = 12 x^{2} - 96 x + 135

Switch sides

12 x^{2} - 96 x + 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 \cdot 12 \cdot 135}{2 \cdot 12}

(- 96)^{2} - 4 \cdot 12 \cdot 135 = 1219

x_{1, 2} = \frac{- ( - 96 ) \pm 12 19}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 12 19}{2 \cdot 12}, x_{2} = \frac{- ( - 96 ) - 12 19}{2 \cdot 12}

x = \frac{- ( - 96 ) + 12 19}{2 \cdot 12} : \frac{8 + 19}{2}

x = \frac{- ( - 96 ) - 12 19}{2 \cdot 12} : \frac{8 - 19}{2}

The solutions to the quadratic equation are:

x = \frac{8 + 19}{2}, x = \frac{8 - 19}{2}

z^{2} = - 12

1 + 3 x^{2} = 0

15 x^{2} - 65 x = 0

49 - 14 x - 2 x^{2} = 0

2 d^{2} - 4 d - 5 = 0

What are the solutions to the equation solvefor x,0=12x^2-96x+135 ?
The solutions to the equation solvefor x,0=12x^2-96x+135 are x=(8+sqrt(19))/2 ,x=(8-sqrt(19))/2
Find the zeros of solvefor x,0=12x^2-96x+135
The zeros of solvefor x,0=12x^2-96x+135 are x=(8+sqrt(19))/2 ,x=(8-sqrt(19))/2