What are the solutions to the equation (x+24)\times (x+2)=420 ?

The solutions to the equation (x+24)\times (x+2)=420 are x=-13+sqrt(541),x=-13-sqrt(541)

Find the zeros of (x+24)\times (x+2)=420

The zeros of (x+24)\times (x+2)=420 are x=-13+sqrt(541),x=-13-sqrt(541)

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(x + 24) \cdot (x + 2) = 420

x = - 13 + 541, x = - 13 - 541

Decimal

x = 10.25940 \dots, x = - 36.25940 \dots

Solution steps

(x + 24) (x + 2) = 420

Expand

(x + 24) (x + 2) : x^{2} + 26 x + 48

x^{2} + 26 x + 48 = 420

Move

420

to the left side

x^{2} + 26 x - 372 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 1 \cdot ( - 372 )}{2 \cdot 1}

2 6^{2} - 4 \cdot 1 \cdot (- 372) = 2541

x_{1, 2} = \frac{- 26 \pm 2 541}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 26 + 2 541}{2 \cdot 1}, x_{2} = \frac{- 26 - 2 541}{2 \cdot 1}

x = \frac{- 26 + 2 541}{2 \cdot 1} : - 13 + 541

x = \frac{- 26 - 2 541}{2 \cdot 1} : - 13 - 541

The solutions to the quadratic equation are:

x = - 13 + 541, x = - 13 - 541

0 = x^{2} + 5 x - 24

- 12 x - 9 = 4 x^{2}

x, z = 1 - x^{2} - y^{2}

- 8 x^{2} - 33 = - 9 x^{2} + 8 x

3 x^{2} - 2 = x^{2} + 6

What are the solutions to the equation (x+24)\times (x+2)=420 ?
The solutions to the equation (x+24)\times (x+2)=420 are x=-13+sqrt(541),x=-13-sqrt(541)
Find the zeros of (x+24)\times (x+2)=420
The zeros of (x+24)\times (x+2)=420 are x=-13+sqrt(541),x=-13-sqrt(541)