What are the solutions to the equation 4(10-5x)^2=49 ?

The solutions to the equation 4(10-5x)^2=49 are x= 13/10 ,x= 27/10

Find the zeros of 4(10-5x)^2=49

The zeros of 4(10-5x)^2=49 are x= 13/10 ,x= 27/10

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4 (10 - 5 x)^{2} = 49

x = \frac{13}{10}, x = \frac{27}{10}

Decimal

x = 1.3, x = 2.7

Solution steps

4 (10 - 5 x)^{2} = 49

Divide both sides by

4

(10 - 5 x)^{2} = \frac{49}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

10 - 5 x = \frac{49}{4} : x = \frac{13}{10}

Solve

10 - 5 x = - \frac{49}{4} : x = \frac{27}{10}

The solutions to the quadratic equation are:

x = \frac{13}{10}, x = \frac{27}{10}

x^{2} - 2 x - 4

x, x^{2} + 2 y^{2} + z^{2} - 4 x + 4 y - 2 z + 3 = 0

180 + 6 q - 4 q^{2} = 2 q^{2}

24 x^{2} + 15 x = 0

x^{2} + 11 x - 4 = 0

What are the solutions to the equation 4(10-5x)^2=49 ?
The solutions to the equation 4(10-5x)^2=49 are x= 13/10 ,x= 27/10
Find the zeros of 4(10-5x)^2=49
The zeros of 4(10-5x)^2=49 are x= 13/10 ,x= 27/10