What are the solutions to the equation factor 2x^2-6=11 ?

The solutions to the equation factor 2x^2-6=11 are x=-sqrt(17/2),x=sqrt(17/2)

Find the zeros of factor 2x^2-6=11

The zeros of factor 2x^2-6=11 are x=-sqrt(17/2),x=sqrt(17/2)

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2 x^{2} - 6 = 11

x = - \frac{17}{2}, x = \frac{17}{2}

Decimal

x = - 2.91547 \dots, x = 2.91547 \dots

Solution steps

2 x^{2} - 6 = 11

Move

11

to the left side

2 x^{2} - 17 = 0

Factor

2 x^{2} - 17 : (2 x + 17) (2 x - 17)

(2 x + 17) (2 x - 17) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 17 = 0 or 2 x - 17 = 0

Solve

2 x + 17 = 0 : x = - \frac{17}{2}

Solve

2 x - 17 = 0 : x = \frac{17}{2}

The solutions to the quadratic equation are:

x = - \frac{17}{2}, x = \frac{17}{2}

2 x + 3 = x^{2} + x + 1

2 x^{2} + 2 x + 1

x^{2} + (x - 1)^{2} = 1

(x + 20)^{2} = 625

x^{2} - (2 x + 1)^{2} = - 21

What are the solutions to the equation factor 2x^2-6=11 ?
The solutions to the equation factor 2x^2-6=11 are x=-sqrt(17/2),x=sqrt(17/2)
Find the zeros of factor 2x^2-6=11
The zeros of factor 2x^2-6=11 are x=-sqrt(17/2),x=sqrt(17/2)