What are the solutions to the equation -20w=4w^2+25 ?

The solutions to the equation -20w=4w^2+25 are w=-5/2

Find the zeros of -20w=4w^2+25

The zeros of -20w=4w^2+25 are w=-5/2

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- 20 w = 4 w^{2} + 25

w = - \frac{5}{2}

Decimal

w = - 2.5

Solution steps

- 20 w = 4 w^{2} + 25

Switch sides

4 w^{2} + 25 = - 20 w

Move

20 w

to the left side

4 w^{2} + 25 + 20 w = 0

Write in the standard form

a x^{2} + b x + c = 0

4 w^{2} + 20 w + 25 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

w_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

w = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

w = - \frac{5}{2}

The solution to the quadratic equation is:

w = - \frac{5}{2}

c^{2} = 36

x^{2} - 8 = 0

3 x^{2} + 7 x = 2 x - 5

x^{2} - 20 x + 16 = 0

a x^{2} - x (2 a^{2} + 1) + 2 a = 0

What are the solutions to the equation -20w=4w^2+25 ?
The solutions to the equation -20w=4w^2+25 are w=-5/2
Find the zeros of -20w=4w^2+25
The zeros of -20w=4w^2+25 are w=-5/2