What are the solutions to the equation 6x^2+4x-18=0 ?

The solutions to the equation 6x^2+4x-18=0 are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3

Find the zeros of 6x^2+4x-18=0

The zeros of 6x^2+4x-18=0 are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 4 x - 18 = 0

x = \frac{- 1 + 2 7}{3}, x = - \frac{1 + 2 7}{3}

Decimal

x = 1.43050 \dots, x = - 2.09716 \dots

Solution steps

6 x^{2} + 4 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 ( - 18 )}{2 \cdot 6}

4^{2} - 4 \cdot 6 (- 18) = 87

x_{1, 2} = \frac{- 4 \pm 8 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 4 + 8 7}{2 \cdot 6}, x_{2} = \frac{- 4 - 8 7}{2 \cdot 6}

x = \frac{- 4 + 8 7}{2 \cdot 6} : \frac{- 1 + 2 7}{3}

x = \frac{- 4 - 8 7}{2 \cdot 6} : - \frac{1 + 2 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2 7}{3}, x = - \frac{1 + 2 7}{3}

x, x^{2} + 4 y^{2} + 9 z^{2} = 1

(2 x - a)^{2} = 4 a^{2}

6 x^{2} - 5 x - 2 = - 6 x^{2}

10 n^{2} = n^{2} + 16

3 x^{2} + 12 x = 7 x + 2

What are the solutions to the equation 6x^2+4x-18=0 ?
The solutions to the equation 6x^2+4x-18=0 are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3
Find the zeros of 6x^2+4x-18=0
The zeros of 6x^2+4x-18=0 are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3