What are the solutions to the equation 6x^2-5x-2=-6x^2 ?

The solutions to the equation 6x^2-5x-2=-6x^2 are x= 2/3 ,x=-1/4

Find the zeros of 6x^2-5x-2=-6x^2

The zeros of 6x^2-5x-2=-6x^2 are x= 2/3 ,x=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} - 5 x - 2 = - 6 x^{2}

x = \frac{2}{3}, x = - \frac{1}{4}

Decimal

x = 0.66666 \dots, x = - 0.25

Solution steps

6 x^{2} - 5 x - 2 = - 6 x^{2}

Move

6 x^{2}

to the left side

12 x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 12 ( - 2 )}{2 \cdot 12}

(- 5)^{2} - 4 \cdot 12 (- 2) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 12}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 12}

x = \frac{- ( - 5 ) + 11}{2 \cdot 12} : \frac{2}{3}

x = \frac{- ( - 5 ) - 11}{2 \cdot 12} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{1}{4}

10 n^{2} = n^{2} + 16

3 x^{2} + 12 x = 7 x + 2

48 x^{2} + 132 x - 36 = 0

4 t^{2} + 4 t - 1 = 0

x^{2} - 5 x - 1 = - 1

What are the solutions to the equation 6x^2-5x-2=-6x^2 ?
The solutions to the equation 6x^2-5x-2=-6x^2 are x= 2/3 ,x=-1/4
Find the zeros of 6x^2-5x-2=-6x^2
The zeros of 6x^2-5x-2=-6x^2 are x= 2/3 ,x=-1/4