12x-4-x^2=0

Lösung

12 x - 4 - x^{2} = 0

x = 2 (3 - 22), x = 2 (3 + 22)

Dezimale

x = 0.34314 \dots, x = 11.65685 \dots

Schritte zur Lösung

12 x - 4 - x^{2} = 0

Schreibe in der Standard Form

a x^{2} + b x + c = 0

- x^{2} + 12 x - 4 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

1 2^{2} - 4 (- 1) (- 4) = 82

x_{1, 2} = \frac{- 12 \pm 8 2}{2 ( - 1 )}

Trenne die Lösungen

x_{1} = \frac{- 12 + 8 2}{2 ( - 1 )}, x_{2} = \frac{- 12 - 8 2}{2 ( - 1 )}

x = \frac{- 12 + 8 2}{2 ( - 1 )} : 2 (3 - 22)

x = \frac{- 12 - 8 2}{2 ( - 1 )} : 2 (3 + 22)

Die Lösungen für die quadratische Gleichung sind:

x = 2 (3 - 22), x = 2 (3 + 22)

X^{2} = 81

co m pl e t es q u a re x^{2} + 3 x - 6 = 0

4 x^{2} + 75 = 0

9 x^{2} - 2880 = 0

2 n^{2} + 14 n + 8 = - 5