What are the solutions to the equation roots s^2+2s+6 ?

The solutions to the equation roots s^2+2s+6 are s=-1+sqrt(5)i,s=-1-sqrt(5)i

Find the zeros of roots s^2+2s+6

The zeros of roots s^2+2s+6 are s=-1+sqrt(5)i,s=-1-sqrt(5)i

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roots

s^{2} + 2 s + 6

s = - 1 + 5 i, s = - 1 - 5 i

Solution steps

s^{2} + 2 s + 6

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 2 s + 6 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 6 : 25 i

s_{1, 2} = \frac{- 2 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 5 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 5 i}{2 \cdot 1}

s = \frac{- 2 + 2 5 i}{2 \cdot 1} : - 1 + 5 i

s = \frac{- 2 - 2 5 i}{2 \cdot 1} : - 1 - 5 i

The solutions to the quadratic equation are:

s = - 1 + 5 i, s = - 1 - 5 i

1459264 x^{2} + 24288.75 x - 2147391.52 = 0

4 x^{2} + 75 = 0

9 x^{2} - 2880 = 0

2 n^{2} + 14 n + 8 = - 5

4 x^{2} = x^{2} + 3

What are the solutions to the equation roots s^2+2s+6 ?
The solutions to the equation roots s^2+2s+6 are s=-1+sqrt(5)i,s=-1-sqrt(5)i
Find the zeros of roots s^2+2s+6
The zeros of roots s^2+2s+6 are s=-1+sqrt(5)i,s=-1-sqrt(5)i