What are the solutions to the equation x^2-15x-39=-30 ?

The solutions to the equation x^2-15x-39=-30 are x=(15+3sqrt(29))/2 ,x=(15-3sqrt(29))/2

Find the zeros of x^2-15x-39=-30

The zeros of x^2-15x-39=-30 are x=(15+3sqrt(29))/2 ,x=(15-3sqrt(29))/2

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x^{2} - 15 x - 39 = - 30

x = \frac{15 + 3 29}{2}, x = \frac{15 - 3 29}{2}

Decimal

x = 15.57774 \dots, x = - 0.57774 \dots

Solution steps

x^{2} - 15 x - 39 = - 30

Move

30

to the left side

x^{2} - 15 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot (- 9) = 329

x_{1, 2} = \frac{- ( - 15 ) \pm 3 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3 29}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 3 29}{2 \cdot 1}

x = \frac{- ( - 15 ) + 3 29}{2 \cdot 1} : \frac{15 + 3 29}{2}

x = \frac{- ( - 15 ) - 3 29}{2 \cdot 1} : \frac{15 - 3 29}{2}

The solutions to the quadratic equation are:

x = \frac{15 + 3 29}{2}, x = \frac{15 - 3 29}{2}

- 16 x^{2} = 200

x, x^{2} - 2 = 2 x - 2

3 x^{2} + 3 x + \frac{1}{2} = 0

\frac{1}{4} (x - 4)^{2} + 1 = 0

x^{2} - x - 8 = 2 x^{2} - 2 x - 14

What are the solutions to the equation x^2-15x-39=-30 ?
The solutions to the equation x^2-15x-39=-30 are x=(15+3sqrt(29))/2 ,x=(15-3sqrt(29))/2
Find the zeros of x^2-15x-39=-30
The zeros of x^2-15x-39=-30 are x=(15+3sqrt(29))/2 ,x=(15-3sqrt(29))/2