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受欢迎的代数 >

0=50+20t-4.9t^2

解答

0 = 50 + 20 \cdot t - 4.9 \cdot t^{2}

解答

t = - \frac{10 ( 345 - 10 )}{49}, t = \frac{10 ( 10 + 345 )}{49}

+1

十进制

t = - 1.74983 \dots, t = 5.83146 \dots

求解步骤

0 = 50 + 20 t - 4.9 t^{2}

在两边乘以

10

0 = 500 + 200 t - 49 t^{2}

交换两边

500 + 200 t - 49 t^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

- 49 t^{2} + 200 t + 500 = 0

使用求根公式求解

t_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 ( - 49 ) \cdot 500}{2 ( - 49 )}

20 0^{2} - 4 (- 49) \cdot 500 = 20345

t_{1, 2} = \frac{- 200 \pm 20 345}{2 ( - 49 )}

将解分隔开

t_{1} = \frac{- 200 + 20 345}{2 ( - 49 )}, t_{2} = \frac{- 200 - 20 345}{2 ( - 49 )}

t = \frac{- 200 + 20 345}{2 ( - 49 )} : - \frac{10 ( 345 - 10 )}{49}

t = \frac{- 200 - 20 345}{2 ( - 49 )} : \frac{10 ( 10 + 345 )}{49}

二次方程组的解是:

t = - \frac{10 ( 345 - 10 )}{49}, t = \frac{10 ( 10 + 345 )}{49}

作图

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