What are the solutions to the equation sqrt(13)x^2=16 ?

The solutions to the equation sqrt(13)x^2=16 are x= 4/(sqrt(\sqrt{13))},x=-4/(sqrt(\sqrt{13))}

Find the zeros of sqrt(13)x^2=16

The zeros of sqrt(13)x^2=16 are x= 4/(sqrt(\sqrt{13))},x=-4/(sqrt(\sqrt{13))}

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13 x^{2} = 16

x = \frac{4}{13}, x = - \frac{4}{13}

Decimal

x = 2.10656 \dots, x = - 2.10656 \dots

Solution steps

13 x^{2} = 16

Divide both sides by

13

x^{2} = \frac{16}{13}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{13}, x = - \frac{16}{13}

\frac{16}{13} = \frac{4}{13}

- \frac{16}{13} = - \frac{4}{13}

x = \frac{4}{13}, x = - \frac{4}{13}

u (u + 6) = 3

48 = 3 (x - 1)^{2}

x^{2} - 18 = - 7 x

x^{2} - 36 = 12 x

- 2 x^{2} - 5 = 3 x^{2} - 10 x

What are the solutions to the equation sqrt(13)x^2=16 ?
The solutions to the equation sqrt(13)x^2=16 are x= 4/(sqrt(\sqrt{13))},x=-4/(sqrt(\sqrt{13))}
Find the zeros of sqrt(13)x^2=16
The zeros of sqrt(13)x^2=16 are x= 4/(sqrt(\sqrt{13))},x=-4/(sqrt(\sqrt{13))}