What is the answer to solvefor y,e^{sqrt(y)}=x^2 ?

The answer to solvefor y,e^{sqrt(y)}=x^2 is y=4ln^2(x) {x>= 1}

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solvefor y,e^{sqrt(y)}=x^2

solve for

y, e^{y} = x^{2}

y = 4 ln^{2} (x) {x \geq 1}

Solution steps

e^{y} = x^{2}

Apply exponent rules

y = 2 ln (x)

Solve

y = 2 ln (x) : y = 4 ln^{2} (x) {x \geq 1}

y = 4 ln^{2} (x) {x \geq 1}

x + 12 x^{2} = 6

(x) (x) = 2 x

9 x^{2} - 2 x - 3 = 0

x, x^{2} + 4 y^{2} = 4 a y

x^{2} - 4 x - 2 = 0

What is the answer to solvefor y,e^{sqrt(y)}=x^2 ?
The answer to solvefor y,e^{sqrt(y)}=x^2 is y=4ln^2(x) {x>= 1}