What are the solutions to the equation 5x^2-4x-11=3x^2 ?

The solutions to the equation 5x^2-4x-11=3x^2 are x=(2+sqrt(26))/2 ,x=(2-sqrt(26))/2

Find the zeros of 5x^2-4x-11=3x^2

The zeros of 5x^2-4x-11=3x^2 are x=(2+sqrt(26))/2 ,x=(2-sqrt(26))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 4 x - 11 = 3 x^{2}

x = \frac{2 + 26}{2}, x = \frac{2 - 26}{2}

Decimal

x = 3.54950 \dots, x = - 1.54950 \dots

Solution steps

5 x^{2} - 4 x - 11 = 3 x^{2}

Move

3 x^{2}

to the left side

2 x^{2} - 4 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 11) = 226

x_{1, 2} = \frac{- ( - 4 ) \pm 2 26}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 26}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 26}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 26}{2 \cdot 2} : \frac{2 + 26}{2}

x = \frac{- ( - 4 ) - 2 26}{2 \cdot 2} : \frac{2 - 26}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 26}{2}, x = \frac{2 - 26}{2}

5 x^{2} + 1 = 21

x^{2} - 8 x + 32 = 0

(5 - 1) x^{2} - 2 x - (5 + 1) = 0

x, h^{- 1} (x) = \frac{1}{2} x^{2}

5 a^{2} - 7 a - 10 = 0

What are the solutions to the equation 5x^2-4x-11=3x^2 ?
The solutions to the equation 5x^2-4x-11=3x^2 are x=(2+sqrt(26))/2 ,x=(2-sqrt(26))/2
Find the zeros of 5x^2-4x-11=3x^2
The zeros of 5x^2-4x-11=3x^2 are x=(2+sqrt(26))/2 ,x=(2-sqrt(26))/2