What are the solutions to the equation 3(5x-7)^2-23=-17 ?

The solutions to the equation 3(5x-7)^2-23=-17 are x=(sqrt(2)+7)/5 ,x=(-sqrt(2)+7)/5

Find the zeros of 3(5x-7)^2-23=-17

The zeros of 3(5x-7)^2-23=-17 are x=(sqrt(2)+7)/5 ,x=(-sqrt(2)+7)/5

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3 (5 x - 7)^{2} - 23 = - 17

x = \frac{2 + 7}{5}, x = \frac{- 2 + 7}{5}

Decimal

x = 1.68284 \dots, x = 1.11715 \dots

Solution steps

3 (5 x - 7)^{2} - 23 = - 17

Move

23

to the right side

3 (5 x - 7)^{2} = 6

Divide both sides by

3

(5 x - 7)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 7 = 2 : x = \frac{2 + 7}{5}

Solve

5 x - 7 = - 2 : x = \frac{- 2 + 7}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 7}{5}, x = \frac{- 2 + 7}{5}

0 = 6 x^{2}

7 v^{2} - 42 = - 35 v

3 x^{2} - 7 x - 6 = 0

2 x^{2} - x - 29 = 15

3 x^{2} - 75 = 0

What are the solutions to the equation 3(5x-7)^2-23=-17 ?
The solutions to the equation 3(5x-7)^2-23=-17 are x=(sqrt(2)+7)/5 ,x=(-sqrt(2)+7)/5
Find the zeros of 3(5x-7)^2-23=-17
The zeros of 3(5x-7)^2-23=-17 are x=(sqrt(2)+7)/5 ,x=(-sqrt(2)+7)/5