What are the solutions to the equation X^2-X=-12 ?

The solutions to the equation X^2-X=-12 are X= 1/2+i(sqrt(47))/2 ,X= 1/2-i(sqrt(47))/2

Find the zeros of X^2-X=-12

The zeros of X^2-X=-12 are X= 1/2+i(sqrt(47))/2 ,X= 1/2-i(sqrt(47))/2

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X^{2} - X = - 12

X = \frac{1}{2} + i \frac{47}{2}, X = \frac{1}{2} - i \frac{47}{2}

Solution steps

X^{2} - X = - 12

Move

12

to the left side

X^{2} - X + 12 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 12 : 47 i

X_{1, 2} = \frac{- ( - 1 ) \pm 47 i}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 1 ) + 47 i}{2 \cdot 1}, X_{2} = \frac{- ( - 1 ) - 47 i}{2 \cdot 1}

X = \frac{- ( - 1 ) + 47 i}{2 \cdot 1} : \frac{1}{2} + i \frac{47}{2}

X = \frac{- ( - 1 ) - 47 i}{2 \cdot 1} : \frac{1}{2} - i \frac{47}{2}

The solutions to the quadratic equation are:

X = \frac{1}{2} + i \frac{47}{2}, X = \frac{1}{2} - i \frac{47}{2}

10 x - 4 = 5 x^{2}

(8 + v) (4 v - 5) = 0

14 h - 40 = 6 h^{2}

4 x^{2} - 29 x - 20 = 0

(2 x - 5) (x + 2) - (x + 2) (3 x - 1) = 0

What are the solutions to the equation X^2-X=-12 ?
The solutions to the equation X^2-X=-12 are X= 1/2+i(sqrt(47))/2 ,X= 1/2-i(sqrt(47))/2
Find the zeros of X^2-X=-12
The zeros of X^2-X=-12 are X= 1/2+i(sqrt(47))/2 ,X= 1/2-i(sqrt(47))/2