What are the solutions to the equation 9p^2+17p+12=3p^2 ?

The solutions to the equation 9p^2+17p+12=3p^2 are p=-4/3 ,p=-3/2

Find the zeros of 9p^2+17p+12=3p^2

The zeros of 9p^2+17p+12=3p^2 are p=-4/3 ,p=-3/2

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9 p^{2} + 17 p + 12 = 3 p^{2}

p = - \frac{4}{3}, p = - \frac{3}{2}

Decimal

p = - 1.33333 \dots, p = - 1.5

Solution steps

9 p^{2} + 17 p + 12 = 3 p^{2}

Move

3 p^{2}

to the left side

6 p^{2} + 17 p + 12 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 6 \cdot 12}{2 \cdot 6}

1 7^{2} - 4 \cdot 6 \cdot 12 = 1

p_{1, 2} = \frac{- 17 \pm 1}{2 \cdot 6}

Separate the solutions

p_{1} = \frac{- 17 + 1}{2 \cdot 6}, p_{2} = \frac{- 17 - 1}{2 \cdot 6}

p = \frac{- 17 + 1}{2 \cdot 6} : - \frac{4}{3}

p = \frac{- 17 - 1}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

p = - \frac{4}{3}, p = - \frac{3}{2}

x^{(2)} - 4 x + 3 = 0

1 x^{2} - 4 x - 5 = 0

4 x^{2} - 5 x = - 1

x^{2} + 9 x + 6

2 x^{2} - 7 = 25

What are the solutions to the equation 9p^2+17p+12=3p^2 ?
The solutions to the equation 9p^2+17p+12=3p^2 are p=-4/3 ,p=-3/2
Find the zeros of 9p^2+17p+12=3p^2
The zeros of 9p^2+17p+12=3p^2 are p=-4/3 ,p=-3/2