What are the solutions to the equation x^{(2)}-4x+3=0 ?

The solutions to the equation x^{(2)}-4x+3=0 are x=3,x=1

Find the zeros of x^{(2)}-4x+3=0

The zeros of x^{(2)}-4x+3=0 are x=3,x=1

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x^{(2)} - 4 x + 3 = 0

x = 3, x = 1

Solution steps

x^{(2)} - 4 x + 3 = 0

Refine

x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

x = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

1 x^{2} - 4 x - 5 = 0

4 x^{2} - 5 x = - 1

x^{2} + 9 x + 6

2 x^{2} - 7 = 25

k, 6 x^{2} + k x + 6 = 0

What are the solutions to the equation x^{(2)}-4x+3=0 ?
The solutions to the equation x^{(2)}-4x+3=0 are x=3,x=1
Find the zeros of x^{(2)}-4x+3=0
The zeros of x^{(2)}-4x+3=0 are x=3,x=1