What are the solutions to the equation x^2+2x+10=-2 ?

The solutions to the equation x^2+2x+10=-2 are x=-1+sqrt(11)i,x=-1-sqrt(11)i

Find the zeros of x^2+2x+10=-2

The zeros of x^2+2x+10=-2 are x=-1+sqrt(11)i,x=-1-sqrt(11)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x + 10 = - 2

x = - 1 + 11 i, x = - 1 - 11 i

Solution steps

x^{2} + 2 x + 10 = - 2

Move

2

to the left side

x^{2} + 2 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 12 : 211 i

x_{1, 2} = \frac{- 2 \pm 2 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 11 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 11 i}{2 \cdot 1}

x = \frac{- 2 + 2 11 i}{2 \cdot 1} : - 1 + 11 i

x = \frac{- 2 - 2 11 i}{2 \cdot 1} : - 1 - 11 i

The solutions to the quadratic equation are:

x = - 1 + 11 i, x = - 1 - 11 i

- 9 x^{2} + 18 x + 35 = 0

7 x^{2} + 40 x = 12

(2 x - 5)^{2} - (x - 6)^{2} = 5

3 x^{2} - 6 x + 14

2 x^{2} - 36 x = - 160

What are the solutions to the equation x^2+2x+10=-2 ?
The solutions to the equation x^2+2x+10=-2 are x=-1+sqrt(11)i,x=-1-sqrt(11)i
Find the zeros of x^2+2x+10=-2
The zeros of x^2+2x+10=-2 are x=-1+sqrt(11)i,x=-1-sqrt(11)i