What are the solutions to the equation 100x^2+50x+3=0 ?

The solutions to the equation 100x^2+50x+3=0 are x=(-5+sqrt(13))/(20),x=-(5+sqrt(13))/(20)

Find the zeros of 100x^2+50x+3=0

The zeros of 100x^2+50x+3=0 are x=(-5+sqrt(13))/(20),x=-(5+sqrt(13))/(20)

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100 x^{2} + 50 x + 3 = 0

x = \frac{- 5 + 13}{20}, x = - \frac{5 + 13}{20}

Decimal

x = - 0.06972 \dots, x = - 0.43027 \dots

Solution steps

100 x^{2} + 50 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 100 \cdot 3}{2 \cdot 100}

5 0^{2} - 4 \cdot 100 \cdot 3 = 1013

x_{1, 2} = \frac{- 50 \pm 10 13}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 50 + 10 13}{2 \cdot 100}, x_{2} = \frac{- 50 - 10 13}{2 \cdot 100}

x = \frac{- 50 + 10 13}{2 \cdot 100} : \frac{- 5 + 13}{20}

x = \frac{- 50 - 10 13}{2 \cdot 100} : - \frac{5 + 13}{20}

The solutions to the quadratic equation are:

x = \frac{- 5 + 13}{20}, x = - \frac{5 + 13}{20}

r^{2} - 4 r + 5

25 x^{2} - 9 = 0

x^{2} - 14 x = - 55

13 x^{2} - 26 x + 12 = 0

12 x^{2} = 23

What are the solutions to the equation 100x^2+50x+3=0 ?
The solutions to the equation 100x^2+50x+3=0 are x=(-5+sqrt(13))/(20),x=-(5+sqrt(13))/(20)
Find the zeros of 100x^2+50x+3=0
The zeros of 100x^2+50x+3=0 are x=(-5+sqrt(13))/(20),x=-(5+sqrt(13))/(20)