What are the solutions to the equation -40/3 =-10/3 x^2 ?

The solutions to the equation -40/3 =-10/3 x^2 are x=2,x=-2

Find the zeros of -40/3 =-10/3 x^2

The zeros of -40/3 =-10/3 x^2 are x=2,x=-2

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- \frac{40}{3} = - \frac{10}{3} x^{2}

x = 2, x = - 2

Solution steps

- \frac{40}{3} = - \frac{10}{3} x^{2}

Switch sides

- \frac{10}{3} x^{2} = - \frac{40}{3}

Multiply both sides by

3

- 10 x^{2} = - 40

Divide both sides by

- 10

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

(x - 11)^{2} - 81 = 0

4800008 x^{2} = 0.0233 - x

d^{2} - 12 d - 14 = - 6 d

12 y^{2} + 19 y + 5 = 0

x^{2} = - 5 x

What are the solutions to the equation -40/3 =-10/3 x^2 ?
The solutions to the equation -40/3 =-10/3 x^2 are x=2,x=-2
Find the zeros of -40/3 =-10/3 x^2
The zeros of -40/3 =-10/3 x^2 are x=2,x=-2