What are the solutions to the equation w^2+8w-6=0 ?

The solutions to the equation w^2+8w-6=0 are w=-4+sqrt(22),w=-4-sqrt(22)

Find the zeros of w^2+8w-6=0

The zeros of w^2+8w-6=0 are w=-4+sqrt(22),w=-4-sqrt(22)

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w^{2} + 8 w - 6 = 0

w = - 4 + 22, w = - 4 - 22

Decimal

w = 0.69041 \dots, w = - 8.69041 \dots

Solution steps

w^{2} + 8 w - 6 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 6) = 222

w_{1, 2} = \frac{- 8 \pm 2 22}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 8 + 2 22}{2 \cdot 1}, w_{2} = \frac{- 8 - 2 22}{2 \cdot 1}

w = \frac{- 8 + 2 22}{2 \cdot 1} : - 4 + 22

w = \frac{- 8 - 2 22}{2 \cdot 1} : - 4 - 22

The solutions to the quadratic equation are:

w = - 4 + 22, w = - 4 - 22

r^{2} + 16

0.513 x \frac{0.05}{4} = x^{2}

r^{2} + 2 r + 64 = 0

6 x^{2} + 22 x = 8

16 (9 - 2 x)^{2} = 36

What are the solutions to the equation w^2+8w-6=0 ?
The solutions to the equation w^2+8w-6=0 are w=-4+sqrt(22),w=-4-sqrt(22)
Find the zeros of w^2+8w-6=0
The zeros of w^2+8w-6=0 are w=-4+sqrt(22),w=-4-sqrt(22)