What are the solutions to the equation x^2-16x+13=-10x ?

The solutions to the equation x^2-16x+13=-10x are x=3+2i,x=3-2i

Find the zeros of x^2-16x+13=-10x

The zeros of x^2-16x+13=-10x are x=3+2i,x=3-2i

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x^{2} - 16 x + 13 = - 10 x

x = 3 + 2 i, x = 3 - 2 i

Solution steps

x^{2} - 16 x + 13 = - 10 x

Move

10 x

to the left side

x^{2} - 6 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 13 : 4 i

x_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4 i}{2 \cdot 1} : 3 + 2 i

x = \frac{- ( - 6 ) - 4 i}{2 \cdot 1} : 3 - 2 i

The solutions to the quadratic equation are:

x = 3 + 2 i, x = 3 - 2 i

x^{2} - 21 x + 81 = 0

q^{2} - 350 q + 25000 = 0

6 x^{2} - 13 + 6 = 0

x^{2} + 12 x + 37

3 u^{2} = 27 u

What are the solutions to the equation x^2-16x+13=-10x ?
The solutions to the equation x^2-16x+13=-10x are x=3+2i,x=3-2i
Find the zeros of x^2-16x+13=-10x
The zeros of x^2-16x+13=-10x are x=3+2i,x=3-2i