What is the answer to 2-1/(x+1)= 1/(x^2+x) ?

The answer to 2-1/(x+1)= 1/(x^2+x) is x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2-1/(x+1)= 1/(x^2+x)

2 - \frac{1}{x + 1} = \frac{1}{x ^{2} + x}

x = \frac{1}{2}

Decimal

x = 0.5

Solution steps

2 - \frac{1}{x + 1} = \frac{1}{x ^{2} + x}

Multiply by LCM

2 x (x + 1) - x = 1

Solve

2 x (x + 1) - x = 1 : x = \frac{1}{2}, x = - 1

x = \frac{1}{2}, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0

Since the equation is undefined for:

- 1

x = \frac{1}{2}

\frac{1}{x} = \frac{3}{15}

\frac{8}{x} + 2 = \frac{x + 4}{x - 6}

\frac{x - 14}{x - 12} = \frac{7}{8}

\frac{2 x}{x - 3} = 1 - \frac{6}{x - 3}

\frac{4}{x - 2} = 3

What is the answer to 2-1/(x+1)= 1/(x^2+x) ?
The answer to 2-1/(x+1)= 1/(x^2+x) is x= 1/2
Solve for x: 2-1/(x+1)= 1/(x^2+x)
The solution is x= 1/2