What is the answer to (40}{x-2}-\frac{40)/x-1=0 ?

The answer to (40}{x-2}-\frac{40)/x-1=0 is x=-8,x=10

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(40}{x-2}-\frac{40)/x-1=0

\frac{40}{x - 2} - \frac{40}{x} - 1 = 0

x = - 8, x = 10

Solution steps

\frac{40}{x - 2} - \frac{40}{x} - 1 = 0

Multiply by LCM

40 x - 40 (x - 2) - x (x - 2) = 0

Solve

40 x - 40 (x - 2) - x (x - 2) = 0 : x = - 8, x = 10

x = - 8, x = 10

Verify Solutions

Find undefined (singularity) points:

x = 2, x = 0

Combine undefined points with solutions:

x = - 8, x = 10

\frac{3}{x + 1} + \frac{2}{7} = 2

\frac{3}{x - 19} = \frac{19}{x - 3}

- \frac{9}{x - 9} - 1 = \frac{x}{x - 9}

\frac{3}{x ^{2} + 6 x - 24} = 1

\frac{x}{x ^{2} - 4} + \frac{1}{x + 2} = 3

What is the answer to (40}{x-2}-\frac{40)/x-1=0 ?
The answer to (40}{x-2}-\frac{40)/x-1=0 is x=-8,x=10
Solve for x: (40}{x-2}-\frac{40)/x-1=0
The solution is x=-8,x=10