What is the answer to (9x)/(x-1)-1= 9/(x^2-x) ?

The answer to (9x)/(x-1)-1= 9/(x^2-x) is x=-9/8

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(9x)/(x-1)-1= 9/(x^2-x)

\frac{9 x}{x - 1} - 1 = \frac{9}{x ^{2} - x}

x = - \frac{9}{8}

Decimal

x = - 1.125

Solution steps

\frac{9 x}{x - 1} - 1 = \frac{9}{x ^{2} - x}

Multiply by LCM

9 x^{2} - x (x - 1) = 9

Solve

9 x^{2} - x (x - 1) = 9 : x = 1, x = - \frac{9}{8}

x = 1, x = - \frac{9}{8}

Verify Solutions

Find undefined (singularity) points:

x = 1, x = 0

Since the equation is undefined for:

1

x = - \frac{9}{8}

\frac{x}{x + 2} = \frac{10}{15}

1 - \frac{2 x - 3}{x + 5} = \frac{x - 2}{10}

t, v = \frac{d}{t}

\frac{2}{x + 2} + \frac{3}{x} = \frac{- x}{x + 2}

x - \frac{3}{x + 7} = \frac{5}{x + 7}

What is the answer to (9x)/(x-1)-1= 9/(x^2-x) ?
The answer to (9x)/(x-1)-1= 9/(x^2-x) is x=-9/8
Solve for x: (9x)/(x-1)-1= 9/(x^2-x)
The solution is x=-9/8