What is the answer to solvefor y,x= 1/(y-1) ?

The answer to solvefor y,x= 1/(y-1) is y= 1/x+1;\quad x\ne 0

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solvefor y,x= 1/(y-1)

solve for

y, x = \frac{1}{y - 1}

y = \frac{1}{x} + 1; x \neq = 0

Solution steps

x = \frac{1}{y - 1}

Multiply both sides by

y - 1

x (y - 1) = 1

Divide both sides by

x; x \neq = 0

y - 1 = \frac{1}{x}; x \neq = 0

Move

1

to the right side

y = \frac{1}{x} + 1; x \neq = 0

- 7 + \frac{9}{x - 9} = - \frac{x}{x - 9}

x^{- 2} - 3 x^{- 1} - 4 = 0

a, \frac{n}{q} = \frac{b}{a}

\frac{x}{x - 2} - \frac{x - 2}{x} = \frac{5}{2}

\frac{1}{x + 7} + \frac{1}{x - 3} = 0

What is the answer to solvefor y,x= 1/(y-1) ?
The answer to solvefor y,x= 1/(y-1) is y= 1/x+1;\quad x\ne 0