What is the answer to 2/(x^2-1)+9/(x+1)=9 ?

The answer to 2/(x^2-1)+9/(x+1)=9 is x=(3+sqrt(17))/6 ,x=(3-sqrt(17))/6

Solve for x: 2/(x^2-1)+9/(x+1)=9

The solution is x=(3+sqrt(17))/6 ,x=(3-sqrt(17))/6

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\frac{2}{x ^{2} - 1} + \frac{9}{x + 1} = 9

x = \frac{3 + 17}{6}, x = \frac{3 - 17}{6}

Decimal

x = 1.18718 \dots, x = - 0.18718 \dots

Solution steps

\frac{2}{x ^{2} - 1} + \frac{9}{x + 1} = 9

Multiply by LCM

2 + 9 (x - 1) = 9 (x + 1) (x - 1)

Solve

2 + 9 (x - 1) = 9 (x + 1) (x - 1) : x = \frac{3 + 17}{6}, x = \frac{3 - 17}{6}

x = \frac{3 + 17}{6}, x = \frac{3 - 17}{6}

Verify Solutions

Find undefined (singularity) points:

x = 1, x = - 1

Combine undefined points with solutions:

x = \frac{3 + 17}{6}, x = \frac{3 - 17}{6}

\frac{1}{2 x} - \frac{1}{x + 2} = \frac{1}{4}

\frac{x}{x ^{2}} = \frac{3}{x}

x + \frac{5}{x - 1} = 7

\frac{x}{x - 2} + 1 = \frac{4}{x ^{2} - 2 x}

\frac{( + 6 )}{x} = (- 3)

What is the answer to 2/(x^2-1)+9/(x+1)=9 ?
The answer to 2/(x^2-1)+9/(x+1)=9 is x=(3+sqrt(17))/6 ,x=(3-sqrt(17))/6
Solve for x: 2/(x^2-1)+9/(x+1)=9
The solution is x=(3+sqrt(17))/6 ,x=(3-sqrt(17))/6