What is the answer to t^{-2}-7t^{-1}+12=0 ?

The answer to t^{-2}-7t^{-1}+12=0 is t= 1/3 ,t= 1/4

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t^{-2}-7t^{-1}+12=0

t^{- 2} - 7 t^{- 1} + 12 = 0

t = \frac{1}{3}, t = \frac{1}{4}

Decimal

t = 0.33333 \dots, t = 0.25

Solution steps

t^{- 2} - 7 t^{- 1} + 12 = 0

Refine

\frac{1}{t ^{2}} - \frac{7}{t} + 12 = 0

Multiply by LCM

1 - 7 t + 12 t^{2} = 0

Solve

1 - 7 t + 12 t^{2} = 0 : t = \frac{1}{3}, t = \frac{1}{4}

t = \frac{1}{3}, t = \frac{1}{4}

Verify Solutions

Find undefined (singularity) points:

t = 0

Combine undefined points with solutions:

t = \frac{1}{3}, t = \frac{1}{4}

0 = 1 + \frac{1}{x ^{2}}

y, \frac{1}{x} + \frac{1}{y} = \frac{1}{2023}

x + \frac{6}{x} = - 5

\frac{1}{x - 1} + 4 = \frac{1}{x ^{2} - x}

- \frac{7}{( x - 4 ) ^{2}} = 0

What is the answer to t^{-2}-7t^{-1}+12=0 ?
The answer to t^{-2}-7t^{-1}+12=0 is t= 1/3 ,t= 1/4
Solve for t: t^{-2}-7t^{-1}+12=0
The solution is t= 1/3 ,t= 1/4