What is the answer to solvefor r,p=(2q+r)/(qr) ?

The answer to solvefor r,p=(2q+r)/(qr) is r=(2q)/(pq-1);\quad q\ne 0,p\ne 1/q

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor r,p=(2q+r)/(qr)

solve for

r, p = \frac{2 q + r}{q r}

r = \frac{2 q}{pq - 1}; q \neq = 0, p \neq = \frac{1}{q}

Solution steps

p = \frac{2 q + r}{q r}

Multiply both sides by

r

p r = \frac{2 q + r}{q}

Multiply both sides by

q

p r q = 2 q + r; q \neq = 0

Move

r

to the left side

p r q - r = 2 q; q \neq = 0

Factor

p r q - r : r (pq - 1)

r (pq - 1) = 2 q; q \neq = 0

Divide both sides by

pq - 1; q \neq = 0, p \neq = \frac{1}{q}

r = \frac{2 q}{pq - 1}; q \neq = 0, p \neq = \frac{1}{q}

\frac{x - 1}{2 x - 4} + \frac{x + 2}{3 x} = 1

\frac{3 x}{x + 1} - \frac{5}{2 x} = \frac{3}{2 x}

x^{4} = \frac{11 x - 6}{6 x - 11}

\frac{3 x + 4}{x ^{2}} = \frac{2}{x}

\frac{x - 7}{x + 3} = \frac{10}{x + 3} - 3

What is the answer to solvefor r,p=(2q+r)/(qr) ?
The answer to solvefor r,p=(2q+r)/(qr) is r=(2q)/(pq-1);\quad q\ne 0,p\ne 1/q