What is the answer to -9/(x^2+3x)+x/(x+3)=-1 ?

The answer to -9/(x^2+3x)+x/(x+3)=-1 is x= 3/2

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-9/(x^2+3x)+x/(x+3)=-1

- \frac{9}{x ^{2} + 3 x} + \frac{x}{x + 3} = - 1

x = \frac{3}{2}

Decimal

x = 1.5

Solution steps

- \frac{9}{x ^{2} + 3 x} + \frac{x}{x + 3} = - 1

Multiply by LCM

- 9 + x^{2} = - x (x + 3)

Solve

- 9 + x^{2} = - x (x + 3) : x = \frac{3}{2}, x = - 3

x = \frac{3}{2}, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 3

Since the equation is undefined for:

- 3

x = \frac{3}{2}

4 - \frac{8}{x + 1} = \frac{8 x}{x + 1}

\frac{12}{x} + \frac{3}{4} = \frac{3}{2}

\frac{14000}{y} + 1500 = \frac{14000}{y - 3}

\frac{3}{x} + \frac{1}{4} = \frac{8}{x}

\frac{x ^{2}}{x ^{2} + 3} = 0

What is the answer to -9/(x^2+3x)+x/(x+3)=-1 ?
The answer to -9/(x^2+3x)+x/(x+3)=-1 is x= 3/2
Solve for x: -9/(x^2+3x)+x/(x+3)=-1
The solution is x= 3/2