What is the answer to (x-9)/(x^2-3x)=(12)/(9-x^2) ?

The answer to (x-9)/(x^2-3x)=(12)/(9-x^2) is x=-9

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(x-9)/(x^2-3x)=(12)/(9-x^2)

\frac{x - 9}{x ^{2} - 3 x} = \frac{12}{9 - x ^{2}}

x = - 9

Solution steps

\frac{x - 9}{x ^{2} - 3 x} = \frac{12}{9 - x ^{2}}

Cross multiply

(x - 9) (9 - x^{2}) = (x^{2} - 3 x) \cdot 12

Solve

(x - 9) (9 - x^{2}) = (x^{2} - 3 x) \cdot 12 : x = 3, x = - 9

x = 3, x = - 9

Verify Solutions

Find undefined (singularity) points:

x = 0, x = 3, x = - 3

Since the equation is undefined for:

3

x = - 9

\frac{x ^{2} + x - 6}{x - 2} = 5

\frac{4}{x + 3} = \frac{6}{x}

\frac{1}{x} + \frac{x - 1}{x ^{2}} = 0

\frac{5}{2 y} - \frac{1}{y} = \frac{3}{4}

x - \frac{7}{x - 8} = 2 x

What is the answer to (x-9)/(x^2-3x)=(12)/(9-x^2) ?
The answer to (x-9)/(x^2-3x)=(12)/(9-x^2) is x=-9
Solve for x: (x-9)/(x^2-3x)=(12)/(9-x^2)
The solution is x=-9