What is the answer to 1/(ax)= 1/(bx)-1/c ?

The answer to 1/(ax)= 1/(bx)-1/c is x=-(bc-ac)/(ab);\quad a\ne 0

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1/(ax)= 1/(bx)-1/c

\frac{1}{a x} = \frac{1}{b x} - \frac{1}{c}

x = - \frac{b c - a c}{ab}; a \neq = 0

Solution steps

\frac{1}{a x} = \frac{1}{b x} - \frac{1}{c}

Multiply by LCM

b c = a c - ab x

Switch sides

a c - ab x = b c

Move

a c

to the right side

- ab x = b c - a c

Divide both sides by

- ab; a \neq = 0

x = - \frac{b c - a c}{ab}; a \neq = 0

1 + \frac{2}{x + 1} = \frac{2}{x ^{2} + 3 x + 2}

\frac{1}{4 x} + 1 = \frac{2}{5 x} - 2

x - \frac{30}{x} = - 1

6 x - \frac{24}{x} = 0

F, \frac{d}{F} = j

What is the answer to 1/(ax)= 1/(bx)-1/c ?
The answer to 1/(ax)= 1/(bx)-1/c is x=-(bc-ac)/(ab);\quad a\ne 0