What is the answer to 6/(x^2-9)-1/(x-3)=1 ?

The answer to 6/(x^2-9)-1/(x-3)=1 is x=-4

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6/(x^2-9)-1/(x-3)=1

\frac{6}{x ^{2} - 9} - \frac{1}{x - 3} = 1

x = - 4

Solution steps

\frac{6}{x ^{2} - 9} - \frac{1}{x - 3} = 1

Multiply by LCM

6 - (x + 3) = (x + 3) (x - 3)

Solve

6 - (x + 3) = (x + 3) (x - 3) : x = 3, x = - 4

x = 3, x = - 4

Verify Solutions

Find undefined (singularity) points:

x = 3, x = - 3

Since the equation is undefined for:

3

x = - 4

\frac{x - 3}{x} = \frac{- 8}{x + 3}

14 = \frac{7 x}{9 + 4 x}

\frac{5 x}{x - 2} = 7 + \frac{10}{x - 2}

\frac{x + 2}{x + 8} = \frac{1}{x + 2}

\frac{2 x ^{2} - 5}{x + 1} = x - 1

What is the answer to 6/(x^2-9)-1/(x-3)=1 ?
The answer to 6/(x^2-9)-1/(x-3)=1 is x=-4
Solve for x: 6/(x^2-9)-1/(x-3)=1
The solution is x=-4