What is the answer to 1-7/(x+3)= 7/(x^2+5x+6) ?

The answer to 1-7/(x+3)= 7/(x^2+5x+6) is x=5

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1-7/(x+3)= 7/(x^2+5x+6)

1 - \frac{7}{x + 3} = \frac{7}{x ^{2} + 5 x + 6}

x = 5

Solution steps

1 - \frac{7}{x + 3} = \frac{7}{x ^{2} + 5 x + 6}

Multiply by LCM

(x + 3) (x + 2) - 7 (x + 2) = 7

Solve

(x + 3) (x + 2) - 7 (x + 2) = 7 : x = 5, x = - 3

x = 5, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 3, x = - 2

Since the equation is undefined for:

- 3

x = 5

\frac{24}{10 + x} + 1 = \frac{24}{10 - x}

\frac{3}{y} - \frac{4}{5} = - \frac{1}{5}

- \frac{1}{5} + \frac{5}{6 x} = - \frac{1}{4 x}

\frac{x - 3}{x + 5} = \frac{x - 5}{x + 3}

1 + \frac{7}{x - 4} = \frac{2}{x ^{2} - 16}

What is the answer to 1-7/(x+3)= 7/(x^2+5x+6) ?
The answer to 1-7/(x+3)= 7/(x^2+5x+6) is x=5
Solve for x: 1-7/(x+3)= 7/(x^2+5x+6)
The solution is x=5