What is the answer to 1+7/(x-4)= 2/(x^2-16) ?

The answer to 1+7/(x-4)= 2/(x^2-16) is x=-2,x=-5

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1+7/(x-4)= 2/(x^2-16)

1 + \frac{7}{x - 4} = \frac{2}{x ^{2} - 16}

x = - 2, x = - 5

Solution steps

1 + \frac{7}{x - 4} = \frac{2}{x ^{2} - 16}

Multiply by LCM

(x - 4) (x + 4) + 7 (x + 4) = 2

Solve

(x - 4) (x + 4) + 7 (x + 4) = 2 : x = - 2, x = - 5

x = - 2, x = - 5

Verify Solutions

Find undefined (singularity) points:

x = 4, x = - 4

Combine undefined points with solutions:

x = - 2, x = - 5

4 x - \frac{4}{x ^{2}} = 0

\frac{6}{x ^{2}} - \frac{40}{x} = 14

x + \frac{2}{x - 2} = \frac{x}{x - 2}

\frac{11}{4} = \frac{5}{x}

9 x + \frac{1}{x + 1} = - \frac{x}{x + 1}

What is the answer to 1+7/(x-4)= 2/(x^2-16) ?
The answer to 1+7/(x-4)= 2/(x^2-16) is x=-2,x=-5
Solve for x: 1+7/(x-4)= 2/(x^2-16)
The solution is x=-2,x=-5