What is the answer to (4x)/(3x+5)+(3x-1)/(2+1)=1 ?

The answer to (4x)/(3x+5)+(3x-1)/(2+1)=1 is x=(-5+sqrt(105))/6 ,x=-(5+sqrt(105))/6

Solve for x: (4x)/(3x+5)+(3x-1)/(2+1)=1

The solution is x=(-5+sqrt(105))/6 ,x=-(5+sqrt(105))/6

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\frac{4 x}{3 x + 5} + \frac{3 x - 1}{2 + 1} = 1

x = \frac{- 5 + 105}{6}, x = - \frac{5 + 105}{6}

Decimal

x = 0.87449 \dots, x = - 2.54115 \dots

Solution steps

\frac{4 x}{3 x + 5} + \frac{3 x - 1}{2 + 1} = 1

Multiply by LCM

12 x + (3 x - 1) (3 x + 5) = 3 (3 x + 5)

Solve

12 x + (3 x - 1) (3 x + 5) = 3 (3 x + 5) : x = \frac{- 5 + 105}{6}, x = - \frac{5 + 105}{6}

x = \frac{- 5 + 105}{6}, x = - \frac{5 + 105}{6}

Verify Solutions

Find undefined (singularity) points:

x = - \frac{5}{3}

Combine undefined points with solutions:

x = \frac{- 5 + 105}{6}, x = - \frac{5 + 105}{6}

\frac{7}{5} = \frac{28}{x}

- \frac{4 x + 8}{x ^{2} - 9} = \frac{5 x + 1}{x + 3}

1 + \frac{1}{x} = \frac{6}{x ^{2}}

\frac{6}{z} = \frac{3}{5}

\frac{3}{x - 3} - \frac{6}{x ^{2}} = 0

What is the answer to (4x)/(3x+5)+(3x-1)/(2+1)=1 ?
The answer to (4x)/(3x+5)+(3x-1)/(2+1)=1 is x=(-5+sqrt(105))/6 ,x=-(5+sqrt(105))/6
Solve for x: (4x)/(3x+5)+(3x-1)/(2+1)=1
The solution is x=(-5+sqrt(105))/6 ,x=-(5+sqrt(105))/6