What is the answer to solvefor y,x=y^{-1} ?

The answer to solvefor y,x=y^{-1} is y= 1/x ;\quad x\ne 0

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solvefor y,x=y^{-1}

solve for

y, x = y^{- 1}

y = \frac{1}{x}; x \neq = 0

Solution steps

x = y^{- 1}

Refine

x = \frac{1}{y}

Multiply both sides by

y

x y = 1

Divide both sides by

x; x \neq = 0

y = \frac{1}{x}; x \neq = 0

1 + \frac{2}{x + 6} = \frac{3 x}{x ^{2} + 3 x - 18}

\frac{2 x}{x ^{2} - 4} = 0

\frac{9}{2} = \frac{7 x - 8}{x + 1}

\frac{15}{x} = \frac{6}{2}

0.25 = \frac{x}{0.005 + x}

What is the answer to solvefor y,x=y^{-1} ?
The answer to solvefor y,x=y^{-1} is y= 1/x ;\quad x\ne 0