What is the answer to 5/(2x-2)=(15)/(x^2-1) ?

The answer to 5/(2x-2)=(15)/(x^2-1) is x=5

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5/(2x-2)=(15)/(x^2-1)

\frac{5}{2 x - 2} = \frac{15}{x ^{2} - 1}

x = 5

Solution steps

\frac{5}{2 x - 2} = \frac{15}{x ^{2} - 1}

Cross multiply

5 (x^{2} - 1) = (2 x - 2) \cdot 15

Solve

5 (x^{2} - 1) = (2 x - 2) \cdot 15 : x = 1, x = 5

x = 1, x = 5

Verify Solutions

Find undefined (singularity) points:

x = 1, x = - 1

Since the equation is undefined for:

1

x = 5

\frac{11}{x - 2} = \frac{11}{2}

\frac{( 2 x e ^{3} + 6 )}{( x + 7 )} = x

\frac{6}{x ^{2}} - \frac{37}{x} = 13

\frac{4}{x ^{2} - 1} + 1 = \frac{x}{x + 1}

3 t + (\frac{4 t - 2}{3 t ^{3}}) = 7

What is the answer to 5/(2x-2)=(15)/(x^2-1) ?
The answer to 5/(2x-2)=(15)/(x^2-1) is x=5
Solve for x: 5/(2x-2)=(15)/(x^2-1)
The solution is x=5