What is the answer to x/(x+1)-1/(x^2+x)=-3 ?

The answer to x/(x+1)-1/(x^2+x)=-3 is x= 1/4

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x/(x+1)-1/(x^2+x)=-3

\frac{x}{x + 1} - \frac{1}{x ^{2} + x} = - 3

x = \frac{1}{4}

Decimal

x = 0.25

Solution steps

\frac{x}{x + 1} - \frac{1}{x ^{2} + x} = - 3

Multiply by LCM

x^{2} - 1 = - 3 x (x + 1)

Solve

x^{2} - 1 = - 3 x (x + 1) : x = \frac{1}{4}, x = - 1

x = \frac{1}{4}, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0

Since the equation is undefined for:

- 1

x = \frac{1}{4}

c, c = \frac{0.05 q ^{2} + 5 q + 500}{q}

\frac{2 x}{x ^{2} + 7} = 0

10 = \frac{1 + 7 x}{7 + x}

\frac{2}{3 x} + \frac{1}{6 x} = \frac{1}{4}

\frac{x - 10}{x - 9} = \frac{10}{11}

What is the answer to x/(x+1)-1/(x^2+x)=-3 ?
The answer to x/(x+1)-1/(x^2+x)=-3 is x= 1/4
Solve for x: x/(x+1)-1/(x^2+x)=-3
The solution is x= 1/4