What is the answer to 0.5=(20x)/(x^2+4) ?

The answer to 0.5=(20x)/(x^2+4) is x=2(10+3sqrt(11)),x=2(10-3sqrt(11))

Solve for x: 0.5=(20x)/(x^2+4)

The solution is x=2(10+3sqrt(11)),x=2(10-3sqrt(11))

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0.5 = \frac{20 x}{x ^{2} + 4}

x = 2 (10 + 311), x = 2 (10 - 311)

Decimal

x = 39.89974 \dots, x = 0.10025 \dots

Solution steps

0.5 = \frac{20 x}{x ^{2} + 4}

Multiply both sides by

x^{2} + 4

0.5 (x^{2} + 4) = 20 x

Solve

0.5 (x^{2} + 4) = 20 x : x = 2 (10 + 311), x = 2 (10 - 311)

x = 2 (10 + 311), x = 2 (10 - 311)

x^{- 1} + x^{- 2} = 1

- \frac{6}{7} - \frac{1}{x + 5} = \frac{2}{x + 5}

6 = \frac{3}{2 x}

\frac{1}{x + 5} + \frac{10}{x ^{2} - 25} = 1

7 - \frac{2}{x - 4} = x

What is the answer to 0.5=(20x)/(x^2+4) ?
The answer to 0.5=(20x)/(x^2+4) is x=2(10+3sqrt(11)),x=2(10-3sqrt(11))
Solve for x: 0.5=(20x)/(x^2+4)
The solution is x=2(10+3sqrt(11)),x=2(10-3sqrt(11))