What is the answer to (-15)/(x^2-5x+6)+1/(x-2)=2 ?

The answer to (-15)/(x^2-5x+6)+1/(x-2)=2 is x= 11/4+i(sqrt(119))/4 ,x= 11/4-i(sqrt(119))/4

Solve for x: (-15)/(x^2-5x+6)+1/(x-2)=2

The solution is x= 11/4+i(sqrt(119))/4 ,x= 11/4-i(sqrt(119))/4

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\frac{- 15}{x ^{2} - 5 x + 6} + \frac{1}{x - 2} = 2

x = \frac{11}{4} + i \frac{119}{4}, x = \frac{11}{4} - i \frac{119}{4}

Solution steps

\frac{- 15}{x ^{2} - 5 x + 6} + \frac{1}{x - 2} = 2

Multiply by LCM

x - 18 = 2 (x - 2) (x - 3)

Solve

x - 18 = 2 (x - 2) (x - 3) : x = \frac{11}{4} + i \frac{119}{4}, x = \frac{11}{4} - i \frac{119}{4}

x = \frac{11}{4} + i \frac{119}{4}, x = \frac{11}{4} - i \frac{119}{4}

\frac{7}{( x - 1 )} = 9

\frac{x - 2}{x - 1} = 2 - \frac{1}{x - 1}

5 + \frac{7}{x + 1} = x

1 = \frac{1}{1 - x} + \frac{x}{x - 1}

\frac{x}{x - 3} + 8 = \frac{9}{x ^{2} - 3 x}

What is the answer to (-15)/(x^2-5x+6)+1/(x-2)=2 ?
The answer to (-15)/(x^2-5x+6)+1/(x-2)=2 is x= 11/4+i(sqrt(119))/4 ,x= 11/4-i(sqrt(119))/4
Solve for x: (-15)/(x^2-5x+6)+1/(x-2)=2
The solution is x= 11/4+i(sqrt(119))/4 ,x= 11/4-i(sqrt(119))/4