What is the answer to 0=2x-4/((x-1)^2) ?

The answer to 0=2x-4/((x-1)^2) is x=2,x=i,x=-i

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0=2x-4/((x-1)^2)

0 = 2 x - \frac{4}{( x - 1 ) ^{2}}

x = 2, x = i, x = - i

Solution steps

0 = 2 x - \frac{4}{( x - 1 ) ^{2}}

Multiply both sides by

(x - 1)^{2}

0 = 2 x (x - 1)^{2} - 4

Solve

0 = 2 x (x - 1)^{2} - 4 : x = 2, x = i, x = - i

x = 2, x = i, x = - i

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 2, x = i, x = - i

\frac{x + 5}{2 x + 3} = \frac{1 - 2 x}{x + 3}

\frac{3}{x} = 3 x + 4

\frac{x - 8}{x + 2} = \frac{x - 1}{2 x + 10}

\frac{x}{2 x - 1} - \frac{6}{4 - x} = 3

\frac{3}{x} + \frac{4}{x + 2} = 1

What is the answer to 0=2x-4/((x-1)^2) ?
The answer to 0=2x-4/((x-1)^2) is x=2,x=i,x=-i
Solve for x: 0=2x-4/((x-1)^2)
The solution is x=2,x=i,x=-i