What is the answer to 5/(x^2+1)-1=0 ?

The answer to 5/(x^2+1)-1=0 is x=2,x=-2

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5/(x^2+1)-1=0

\frac{5}{x ^{2} + 1} - 1 = 0

x = 2, x = - 2

Solution steps

\frac{5}{x ^{2} + 1} - 1 = 0

Multiply both sides by

x^{2} + 1

5 - (x^{2} + 1) = 0

Solve

5 - (x^{2} + 1) = 0 : x = 2, x = - 2

x = 2, x = - 2

\frac{1}{x ^{2} - x} - \frac{1}{x - 1} = - 2

\frac{2}{y} = \frac{1}{y - 2} - 3

y, x = \frac{y - 1}{y + 1}

1 + \frac{x - 2}{x + 1} = 3 x - 5

\frac{x}{2} + \frac{4}{x} = 3