What is the answer to (2x+3)/(x-1)-(x+2)/(3x-4)=0 ?

The answer to (2x+3)/(x-1)-(x+2)/(3x-4)=0 is x=sqrt(2),x=-sqrt(2)

Solve for x: (2x+3)/(x-1)-(x+2)/(3x-4)=0

The solution is x=sqrt(2),x=-sqrt(2)

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Popular >

\frac{2 x + 3}{x - 1} - \frac{x + 2}{3 x - 4} = 0

x = 2, x = - 2

Decimal

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

\frac{2 x + 3}{x - 1} - \frac{x + 2}{3 x - 4} = 0

Multiply by LCM

(2 x + 3) (3 x - 4) - (x + 2) (x - 1) = 0

Solve

(2 x + 3) (3 x - 4) - (x + 2) (x - 1) = 0 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 1, x = \frac{4}{3}

Combine undefined points with solutions:

x = 2, x = - 2

\frac{x ^{3}}{3 x} = 12

t, \frac{r}{t} = d + 10

\frac{2}{x - 3} + \frac{x}{2} = \frac{- 1}{2}

\frac{1}{x} + \frac{1}{x + 1} = \frac{5}{6}

5 x + \frac{1}{x} = - 6

What is the answer to (2x+3)/(x-1)-(x+2)/(3x-4)=0 ?
The answer to (2x+3)/(x-1)-(x+2)/(3x-4)=0 is x=sqrt(2),x=-sqrt(2)
Solve for x: (2x+3)/(x-1)-(x+2)/(3x-4)=0
The solution is x=sqrt(2),x=-sqrt(2)