What is the answer to 2/(y^2-9)= 5/(y^2+3y) ?

The answer to 2/(y^2-9)= 5/(y^2+3y) is y=5

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2/(y^2-9)= 5/(y^2+3y)

\frac{2}{y ^{2} - 9} = \frac{5}{y ^{2} + 3 y}

y = 5

Solution steps

\frac{2}{y ^{2} - 9} = \frac{5}{y ^{2} + 3 y}

Cross multiply

2 (y^{2} + 3 y) = (y^{2} - 9) \cdot 5

Solve

2 (y^{2} + 3 y) = (y^{2} - 9) \cdot 5 : y = - 3, y = 5

y = - 3, y = 5

Verify Solutions

Find undefined (singularity) points:

y = - 3, y = 3, y = 0

Since the equation is undefined for:

- 3

y = 5

x + \frac{x}{x - 5} = \frac{5}{x - 5}

\frac{3}{2} = \frac{3}{x}

R, g = \frac{k}{( R + h ) ^{2}}

\frac{4}{x + 1} - \frac{3}{2} = \frac{6}{3 x + 3}

y, x = \frac{y ^{2} + 3}{3 y ^{2}}

What is the answer to 2/(y^2-9)= 5/(y^2+3y) ?
The answer to 2/(y^2-9)= 5/(y^2+3y) is y=5
Solve for y: 2/(y^2-9)= 5/(y^2+3y)
The solution is y=5