What is the answer to 2x+(16)/(x^2)=0 ?

The answer to 2x+(16)/(x^2)=0 is x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i

Solve for x: 2x+(16)/(x^2)=0

The solution is x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i

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2 x + \frac{16}{x ^{2}} = 0

x = - 2, x = 1 - 3 i, x = 1 + 3 i

Solution steps

2 x + \frac{16}{x ^{2}} = 0

Multiply both sides by

x^{2}

2 x^{3} + 16 = 0

Solve

2 x^{3} + 16 = 0 : x = - 2, x = 1 - 3 i, x = 1 + 3 i

x = - 2, x = 1 - 3 i, x = 1 + 3 i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 2, x = 1 - 3 i, x = 1 + 3 i

0 = 1 - \frac{9}{x ^{2}}

3 - \frac{2}{x + 4} = - \frac{2 x}{x + 4}

\frac{3}{2} + \frac{1}{3} = \frac{1}{x}

\frac{4}{x ^{2}} + \frac{4}{x} = 3

\frac{2}{( x + 1 ) ^{2}} = 0

What is the answer to 2x+(16)/(x^2)=0 ?
The answer to 2x+(16)/(x^2)=0 is x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i
Solve for x: 2x+(16)/(x^2)=0
The solution is x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i